Two masses m 1 = 4 kg and m 2 = 2kg are connected with an inextensible, massless string that passes over a frictionless pulley and through a slit, as shown. The string is vertical on both sides and the string on the left is acted upon by a constant friction force 10 N by the slit as it moves. (use g = 10 m/s 2 )
m/s 2 , downwards.
N.
m/s 2 .
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(a, c)
Sol. Applying NLM on the part that moves through slit.
T 2 – f – T 1 =0
For 4 kg mass 40 – T 2 = 4a
For 2 kg mass T 1 – 20 = 2a
On solving 10 = 6a
a = 
m/s 2
Force exerted on 2kg mass by string = T 1 = 
N.
Tension in the string will not be same throughout, due to the friction force exerted by the slit.
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